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Question
What is the value of the dissociation constant, Kd, for the complex ion Cd(NH3)42+? For Cd(NH3)42+, Kf=1.0x107.
A) 1.0 x10-7
B) 2.5 x106
C) 1.0 x107
D) 5.6 x101
E) 1.0 x10-7
Answer
This answer is hidden. It contains 1 characters.
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Q:
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Q:
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Q:
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Q:
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Q:
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