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Question
When KO2 is dissolved in water the evolution of oxygen takes place according to the reaction
2 KO2(s) + H2O(l) -> O2(g) + 2 K+(aq) + HO2-(aq) + OH-(aq). In this reaction the O2- ion undergoes
A) disproportionation.
B) isomerization.
C) only oxidation.
D) only reduction.
Answer
This answer is hidden. It contains 1 characters.
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