Question

When 31.2 mL of 0.500 M AgNO3 is added to 25.0 mL of 0.300 M NH4Cl, how many grams of AgCl are formed?
AgNO3(aq) + NH4Cl(aq) -> AgCl(s) + NH4NO3(aq)
A) 1.07 g
B) 2.24 g
C) 3.31 g
D) 6.44 g

Answer

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