Question

When 49.4mL of 0.721M lead(II) nitrate reacts with 99.6mL of 0.807M sodium chloride, 0.830kJ of heat is released at constant pressure. What is
for this reaction?
Pb(NO3)2(aq)+2NaCl(aq)→PbCl2(s)+2NaNO3(aq)
A) -23.3 kJ
B) -10.3 kJ
C) -4.23 kJ
D) -7.15 kJ
E) -20.6 kJ

Answer

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