Question

When 0.250 mol of CH4(g) reacts with excess Cl2(g) at constant pressure according to the chemical equation shown below, 177 kJ of heat are released. Calculate the value of H for this reaction, as written.
2 CH4(g) + 3 Cl2(g) -> 2 CHCl3(l) + 3 H2(g) H = ?
A) -1420 kJ
B) -708 kJ
C) +708 kJ
D) +1420 kJ

Answer

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