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Question
When 1.0 mole of acetic acid is diluted with water to a volume of 1.0 L at 25 C, 0.42% of the acetic acid ionizes to form acetate ion and hydronium ion.
CH3CO2H(aq) + H2O(
) 
CH3CO2-(aq) + H3O+(aq)
What percentage of the acid ionizes when 0.75 mole of acetic acid is diluted with water to 1.0 L at 25 C?
Answer
This answer is hidden. It contains 5 characters.
Related questions
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What is the equilibrium constant for reaction below at 25 C? (R = 8.314 J/Kmol)2 NO(g) + O2(g) 2 NO2(g)given DfG [NO(g)] = +86.6 kJ/mol and DfG [NO2(g)] = +51.2 kJ/mol.A.3.9 10-13B.1.0C.2.6 1012D.1.6 106E.3.8 1028
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All of the following relationships are true EXCEPT
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Q:
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Q:
If a chemical reaction is exothermic, but not spontaneous, which of the following must be true?
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