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Question
When the concentration of A is doubled, the rate for the reaction: 
quadruples.
When the concentration of B is doubled the rate remains the same. Which mechanism below is consistent with the experimental observations?
A) Step 1: A + B 
D (fast equilibrium)
Step 2: A + D -> 2 C (slow)
B) Step 1: A + B -> D (slow)
Step 2: A + D 2 C (fast equilibrium)
C) Step 1: 2 A -> D (slow)
Step 2: B + D -> E (fast)
Step 3: E -> 2 C (fast)
D) Step 1: 2 A D (fast equilibrium)
Step 2: B + D -> E (slow)
Step 3: E -> 2 C (fast)
Answer
This answer is hidden. It contains 1 characters.
Related questions
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