Business Communication

Q: Applebee's International, Inc., is a U.S. company that develops, franchises, and operates the Applebee's Neighborhood Grill and Bar restaurant chain. It is the largest chain of casual dining restaurants in the country, with over 1,500 restaurants across the United States. The headquarters is located in Overland Park, Kansas. The company is interested in determining if mean weekly revenue differs among three restaurants in a particular city. The file entitled Applebees contains revenue data for a sample of weeks for each of the three locations. Based on the data gathered by Applebee's, can it be concluded that there is a difference in the average revenue among the three restaurants? A) The p-value = 0.004 < alpha = 0.05. This indicates that we should not reject the null hypothesis and conclude that there is not a difference in the average revenue among the three restaurants. B) The p-value = 0.004 < alpha = 0.05. This indicates that we should reject the null hypothesis and conclude that there exists a difference in the average revenue among the three restaurants. C) The p-value = 0.084 > alpha = 0.05. This indicates that we should not reject the null hypothesis and conclude that there is not a difference in the average revenue among the three restaurants. D) The p-value = 0.084 > alpha = 0.05. This indicates that we should reject the null hypothesis and conclude that there exists a difference in the average revenue among the three restaurants.

Q: Applebee's International, Inc., is a U.S. company that develops, franchises, and operates the Applebee's Neighborhood Grill and Bar restaurant chain. It is the largest chain of casual dining restaurants in the country, with over 1,500 restaurants across the United States. The headquarters is located in Overland Park, Kansas. The company is interested in determining if mean weekly revenue differs among three restaurants in a particular city. The file entitled Applebees contains revenue data for a sample of weeks for each of the three locations.Test to determine if blocking the week on which the testing was done was necessary. Use a significance level of 0.05.A) The p-value = 0.078 > = 0.05. This indicates that inserting the week on which the testing was done was necessary.B) The p-value = 0.078 > = 0.05. This indicates that inserting the week on which the testing was done was not necessary.C) The p-value = 0.000 < = 0.05. This indicates that inserting the week on which the testing was done was necessary.D) The p-value = 0.000 < = 0.05. This indicates that inserting the week on which the testing was done was not necessary.

Q: Frasier and Company manufactures four different products that it ships to customers throughout the United States. Delivery times are not a driving factor in the decision as to which type of carrier to use (rail, plane, or truck) to deliver the product. However, breakage cost is very expensive, and Frasier would like to select a mode of delivery that reduces the amount of product breakage. To help it reach a decision, the managers have decided to examine the dollar amount of breakage incurred by the three alternative modes of transportation under consideration. Because each product's fragility is different, the executives conducting the study wish to control for differences due to type of product. The company randomly assigns each product to each carrier and monitors the dollar breakage that occurs over the course of 100 shipments. The dollar breakage per shipment (to the nearest dollar) is as follows: RailPlaneTruckProduct 1$7,960$8,053$8,818Product 2$8,399$7,764$9,432Product 3$9,429$9,196$9,260Product 4$6,022$5,821$5,676Was Frasier and Company correct in its decision to block for type of product? Conduct the appropriate hypothesis test using a level of significance of 0.01.A) Because F = 32.12 > =0.01 = 9.78, reject the null hypothesis. Thus, based on these sample data we conclude that blocking is effective.B) Because F = 28.14 > =0.01 = 7.63, reject the null hypothesis. Thus, based on these sample data we conclude that blocking is effective.C) Because F = 32.12 > =0.01 = 9.78, do not reject the null hypothesis. Thus, based on these sample data we conclude that blocking is not effective.D) Because F = 28.14 > =0.01 = 7.63, do not reject the null hypothesis. Thus, based on these sample data we conclude that blocking is not effective.

Q: The following sample data were recently collected in the course of conducting a randomized block analysis of variance. Based on these sample data, what conclusions should be reached about blocking effectiveness and about the means of the three populations involved? Test using a significance level equal to 0.05. Block Sample 1 Sample 2 Sample 3 1 30 40 40 2 50 70 50 3 60 40 70 4 40 40 30 5 80 70 90 6 20 10 10 A) Because F = 0.4195 < critical F = 4.103, we do not reject the null hypothesis and conclude that the three populations may have the same mean value. B) Because F = 0.4195 < critical F = 4.103, we reject the null hypothesis and conclude that the three populations do not have the same mean value. C) Because F = 0.1515 < critical F = 4.103, we do not reject the null hypothesis and conclude that the three populations may have the same mean value. D) Because F = 0.1515 < critical F = 4.103, we reject the null hypothesis and conclude that the three populations do not have the same mean value.

Q: Consider the following: Summary Count Sum Average Variance 1 4 443 110.8 468.9 2 4 275 68.8 72.9 3 4 1,030 257.5 1891.7 4 4 300 75.0 433.3 5 4 603 150.8 468.9 6 4 435 108.8 72.9 7 4 1,190 297.5 1891.7 8 4 460 115.0 433.3 Sample 1 8 1,120 140.0 7142.9 Sample 2 8 1,236 154.5 8866.6 Sample 3 8 1,400 175.0 9000.0 Sample 4 8 980 122.5 4307.1 ANOVA Source of Variation SS df MS F p-value F-crit Rows 199,899 7 28557.0 112.8 0.0000 2.488 Columns 11,884 3 3961.3 15.7 0.0000 3.073 Error 5,317 21 253.2 Total 217,100 31 Test the main hypothesis of interest using Î± = 0.05 A) Because F = 15.65 > critical F = 3.0, we reject the null hypothesis and conclude that the four populations do not have the same mean. B) Because F = 15.65 > critical F = 3.0, we do not reject the null hypothesis and conclude that the four populations have the same mean. C) Because F = 125.82 > critical F = 3.0, we reject the null hypothesis and conclude that the four populations do not have the same mean. D) Because F = 125.82 > critical F = 3.0, we do not reject the null hypothesis and conclude that the four populations have the same mean.

Q: Consider the following: Summary Count Sum Average Variance 1 4 443 110.8 468.9 2 4 275 68.8 72.9 3 4 1,030 257.5 1891.7 4 4 300 75.0 433.3 5 4 603 150.8 468.9 6 4 435 108.8 72.9 7 4 1,190 297.5 1891.7 8 4 460 115.0 433.3 Sample 1 8 1,120 140.0 7142.9 Sample 2 8 1,236 154.5 8866.6 Sample 3 8 1,400 175.0 9000.0 Sample 4 8 980 122.5 4307.1 ANOVA Source of Variation SS df MS F p-value F-crit Rows 199,899 7 28557.0 112.8 0.0000 2.488 Columns 11,884 3 3961.3 15.7 0.0000 3.073 Error 5,317 21 253.2 Total 217,100 31 Test to determine whether blocking is effective using an alpha level equal to 0.05 A) Because F = 14.81 > critical F = 2.5, we do not reject the null hypothesis and conclude that blocking is not effective. B) Because F = 14.81 > critical F = 2.5, we reject the null hypothesis and conclude that blocking is effective. C) Because F = 112.79 > critical F = 2.5, we do not reject the null hypothesis and conclude that blocking is not effective. D) Because F = 112.79 > critical F = 2.5, we reject the null hypothesis and conclude that blocking is effective.

Q: A study was conducted to determine if differences in new textbook prices exist between on-campus bookstores, off-campus bookstores, and Internet bookstores. To control for differences in textbook prices that might exist across disciplines, the study randomly selected 12 textbooks and recorded the price of each of the 12 books at each of the three retailers. You may assume normality and equal-variance assumptions have been met. The partially completed ANOVA table based on the study's findings is shown here: ANOVA Source of VariationSSdfMSFTextbooks16,624 Retailer2.4 Error Total17,477.6 Based on the study's findings, can it be concluded that there is a difference in the average price of textbooks across the three retail outlets? Conduct the appropriate hypothesis test at the alpha = 0.10 level of significance.A) F = 0.0411 < =0.10 = 2.56, reject the null hypothesis. Thus, based on these sample data we can conclude that there is a difference in textbook prices at the three different types of retail outlets.B) F = 0.0411 < =0.10 = 2.56, do not reject the null hypothesis. Thus, based on these sample data we cannot conclude that there is a difference in textbook prices at the three different types of retail outlets.C) F = 0.031 < =0.10 = 2.56, reject the null hypothesis. Thus, based on these sample data we can conclude that there is a difference in textbook prices at the three different types of retail outlets.D) F = 0.031 < =0.10 = 2.56, do not reject the null hypothesis. Thus, based on these sample data we cannot conclude that there is a difference in textbook prices at the three different types of retail outlets.

Q: A study was conducted to determine if differences in new textbook prices exist between on-campus bookstores, off-campus bookstores, and Internet bookstores. To control for differences in textbook prices that might exist across disciplines, the study randomly selected 12 textbooks and recorded the price of each of the 12 books at each of the three retailers. You may assume normality and equal-variance assumptions have been met. The partially completed ANOVA table based on the study's findings is shown here: ANOVA Source of VariationSSdfMSFTextbooks16,624 Retailer2.4 Error Total17,477.6 Based on the study's findings, was it correct to block for differences in textbooks? Conduct the appropriate test at the alpha = 0.10 level of significance.A) Since F = 39.05 > =0.10 = 1.88, reject the null hypothesis. This means that based on these sample data we can conclude that blocking is effective.B) Since F = 39.05 > =0.10 = 1.88, do not reject the null hypothesis. This means that based on these sample data we can conclude that blocking is not effective.C) Since F = 40.05 > =0.10 = 1.88, reject the null hypothesis. This means that based on these sample data we can conclude that blocking is effective.D) Since F = 40.05 > =0.10 = 1.88, do not reject the null hypothesis. This means that based on these sample data we can conclude that blocking is not effective

Q: A study was conducted to determine if differences in new textbook prices exist between on-campus bookstores, off-campus bookstores, and Internet bookstores. To control for differences in textbook prices that might exist across disciplines, the study randomly selected 12 textbooks and recorded the price of each of the 12 books at each of the three retailers. You may assume normality and equal-variance assumptions have been met. The partially completed ANOVA table based on the study's findings is shown here: ANOVA Source of Variation SS df MS F Textbooks 16,624 Retailer 2.4 Error Total 17,477.6 Complete the ANOVA table by filling in the missing sums of squares, the degrees of freedom for each source, the mean square, and the calculated F-test statistic for each possible hypothesis test. A) Textbooks df = 11, MSBL = 1,511.3, F (Textbooks) = 40.05, Retailer df = 2, MSB = 1.2, , SSW = 851.2, Error df = 22, MSW = 38.7, Total df = 35 B) Textbooks df = 11, MSBL = 1,511.3, F (Textbooks) = 39.05, Retailer df = 2, MSB = 1.2,, SSW = 851.2, Error df = 22, MSW = 38.7, Total df = 35 C) Textbooks df = 12, MSBL = 1,511.3, F (Textbooks) = 39.05, Retailer df = 2, MSB = 1.2, , SSW = 851.2, Error df = 22, MSW = 38.7, Total df = 36 D) Textbooks df = 11, MSBL = 1,511.3, F (Textbooks) = 39.05, Retailer df = 2, MSB = 1.2, , SSW = 831.2, Error df = 22, MSW = 38.7, Total df = 36

Q: The Lottaburger restaurant chain in central New Mexico is conducting an analysis of its restaurants, which take pride in serving burgers and fries to go faster than the competition. As a part of its analysis, Lottaburger wants to determine if its speed of service is different across its four outlets. Orders at Lottaburger restaurants are tracked electronically, and the chain is able to determine the speed with which every order is filled. The chain decided to randomly sample 20 orders from each of the four restaurants it operates. The speed of service for each randomly sampled order was noted and is contained in the file Lottaburger.At the alpha = 0.05 level of service, can Lottaburger conclude that the speed of service is different across the four restaurants in the chain?A) Since F = 18.418 > =0.05 = 2.725, reject the null hypothesis. Based on these sample data we can conclude that the average service time is different across the four restaurants in the chain.B) Since F = 22.666 > =0.05 = 2.725, reject the null hypothesis. Based on these sample data we can conclude that the average service time is different across the four restaurants in the chain.C) Since F = 22.666 > =0.05 = 2.725, do not reject the null hypothesis. Based on these sample data there is not sufficient evidence to conclude that the average service time is different across the four restaurants in the chain.D) Since F = 18.418 > =0.05 = 2.725, do not reject the null hypothesis. Based on these sample data there is not sufficient evidence to conclude that the average service time is different across the four restaurants in the chain.

Q: Damage to homes caused by burst piping can be expensive to repair. By the time the leak is discovered, hundreds of gallons of water may have already flooded the home. Automatic shutoff valves can prevent extensive water damage from plumbing failures. The valves contain sensors that cut off water flow in the event of a leak, thereby preventing flooding. One important characteristic is the time (in milliseconds) required for the sensor to detect the water leak. Sample data obtained for four different shutoff valves are contained in the file entitled Waterflow. Use the Tukey-Kramer multiple comparison technique to discover any differences in the average detection time. Use a significance level of 0.05. A) The confidence intervals indicate that there is not sufficient evidence to conclude that the average detection time for valve 1, 2, and 3 differ. There is, however, enough evidence to indicate that the average detection time for valve 4 is larger than the other three means. B) The confidence intervals indicate that there is not sufficient evidence to conclude that the average detection time for valve 1, 2, and 4 differ. There is, however, enough evidence to indicate that the average detection time for valve 3 is larger than the other three means. C) The confidence intervals indicate that there is not sufficient evidence to conclude that the average detection time for valve 2 and 4 differ. There is, however, enough evidence to indicate that the average detection time for valve 1 and 3 are larger than the other two means. D) All mean detection times are equal.

Q: Damage to homes caused by burst piping can be expensive to repair. By the time the leak is discovered, hundreds of gallons of water may have already flooded the home. Automatic shutoff valves can prevent extensive water damage from plumbing failures. The valves contain sensors that cut off water flow in the event of a leak, thereby preventing flooding. One important characteristic is the time (in milliseconds) required for the sensor to detect the water leak. Sample data obtained for four different shutoff valves are contained in the file entitled Waterflow. Produce the relevant ANOVA table and conduct a hypothesis test to determine if the mean detection time differs among the four shutoff valve models. Use a significance level of 0.05. A) The ANOVA produces a p-value of 0.033 < alpha = 0.05. Therefore, the null hypothesis is not rejected. There is not sufficient evidence to indicate that the mean detection time differs among the four shutoff valve models B) The ANOVA produces a p-value of 0.033 < alpha = 0.05. Therefore, the null hypothesis is rejected. There is sufficient evidence to indicate that the mean detection time differs among the four shutoff valve models C) The ANOVA produces a p-value of 0.000 < alpha = 0.05. Therefore, the null hypothesis is not rejected. There is not sufficient evidence to indicate that the mean detection time differs among the four shutoff valve models D) The ANOVA produces a p-value of 0.000 < alpha = 0.05. Therefore, the null hypothesis is rejected. There is sufficient evidence to indicate that the mean detection time differs among the four shutoff valve models

Q: In conjunction with the housing foreclosure crisis of 2009, many economists expressed increasing concern about the level of credit card debt and efforts of banks to raise interest rates on these cards. The banks claimed the increases were justified. A Senate subcommittee decided to determine if the average credit card balance depends on the type of credit card used. Under consideration are Visa, MasterCard, Discover, and American Express. The sample sizes to be used for each level are 25, 25, 26, and 23, respectively. State the number of degrees of freedom available for determining the total variation. A) 93 B) 95 C) 98 D) 97

Q: Given the following sample data Item Group 1 Group 2 Group 3 Group 4 1 20.9 28.2 17.8 21.2 2 27.2 26.2 15.9 23.9 3 26.6 21.6 18.4 19.5 4 22.1 29.7 20.2 17.4 5 25.3 30.3 14.1 6 30.1 25.9 7 23.8 Based on the computations for the within- and between-sample variation, develop the ANOVA table and test the appropriate null hypothesis using alpha= 0.05. Use the p-value approach. A) Since p-value = 0.0678 > 0.05 reject H0 and conclude that at least two population means are different. B) Since p-value = 0.000136 < 0.05 reject H0 and conclude that at least two population means are different. C) Since p-value = 0.0678 > 0.05 accept H0 and conclude that all population means are the same. D) Since p-value = 0.000136 < 0.05 accept H0 and conclude that all population means are the same.

Q: Respond to the following questions using this partially completed one-way ANOVA table: Source of Variation SS df MS F-ratio Between Samples 3 Within Samples 405 ____ Total 888 31 Based on the analysis of variance F-test, what conclusion should be reached regarding the null hypothesis? Test using alpha = 0.05. A) Since 11.1309 > 2.9467 accept H0 and conclude that all population means are the same. B) Since 2.9467 > 11.1309 accept H0 and conclude that all population means are the same. C) Since 11.1309 > 2.9467 reject H0 and conclude that at least two populations means are different. D) Since 2.9467 > 11.1309 reject H0 and conclude that at least two populations means are different.

Q: Respond to the following questions using this partially completed one-way ANOVA table: Source of Variation SS df MS F-ratio Between Samples 3 Within Samples 405 ____ Total 888 31 Fill in the ANOVA table with the missing values. A) SSB = 483, MSB = 161, F-ratio = 11.1309, Within Samples df = 28, MSW = 14.464 B) SSB = 483, MSB = 161, F- ratio = 8.1629, Within Samples df = 28, MSW = 14.464 C) SSB = 483, MSB = 161, F-ratio = 8.1629, Within Samples df = 25, MSW = 14.464 D) SSB = 504, MSB = 161, F-ratio = 8.1629, Within Samples df = 28, MSW = 14.464

Q: Respond to the following questions using this partially completed one-way ANOVA table: Source of Variation SS df MS F-ratio Between Samples 1,745 Within Samples ______ 240 Total 6,504 246 Based on the analysis of variance F-test, what conclusion should be reached regarding the null hypothesis? Test using a significance level of 0.01. A) Since 7.948 > 2.8778 accept H0 and conclude that all population means are the same. B) Since 14.667 > 2.8778 accept H0 and conclude that all population means are the same. C) Since 7.948 > 2.8778 reject H0 and conclude that at least two populations means are different. D) Since 14.667 > 2.8778 reject H0 and conclude that at least two populations means are different.

Q: Respond to the following questions using this partially completed one-way ANOVA table: Source of Variation SS df MS F-ratio Between Samples 1,745 Within Samples ______ 240 Total 6,504 246 Fill in the ANOVA table with the missing values. A) Between Samples df = 6, MSB = 290.833, F-ratio = 14.667, SSW = 4,759, MSW = 19.829 B) Between Samples df = 6, MSB = 290.833, F-ratio = 7.948, SSW = 4,759, MSW = 19.829 C) Between Samples df = 5, MSB = 290.833, F-ratio = 14.667, SSW = 4,759, MSW = 19.829 D) Between Samples df = 5, MSB = 290.833, F-ratio = 7.948, SSW = 4,759, MSW = 19.829

Q: A manager is interested in testing whether three populations of interest have equal population means. Simple random samples of size 10 were selected from each population. The following ANOVA table and related statistics were computed: Conduct the appropriate test of the null hypothesis assuming that the populations have equal variances and the populations are normally distributed. Use a 0.05 level of significance. A) Using the F test approach, because F = 3.354 < critical F = 9.84, we reject the null hypothesis and conclude that the population means are not all equal. B) Using the F test approach, because F = 3.354 < critical F = 9.84, we do not reject the null hypothesis and conclude that the population means are all equal. C) Using the F test approach, because F = 9.84 > critical F = 3.35, we reject the null hypothesis and conclude that the population means are not all equal. D) Using the F test approach, because F = 9.84 > critical F = 3.35, we do not reject the null hypothesis and conclude that the population means are all equal.

Q: A start-up cell phone applications company is interested in determining whether house-hold incomes are different for subscribers to three different service providers. A random sample of 25 subscribers to each of the three service providers was taken, and the annual household income for each subscriber was recorded. The partially completed ANOVA table for the analysis is shown here:Based on the sample results, can the start-up firm conclude that there is a difference in household incomes for subscribers to the three service providers? You may assume normal distributions and equal variances. Conduct your test at the alpha= 0.10 level of significance. Be sure to state a critical F-statistic, a decision rule, and a conclusion.A) H0: 1 = 2 = 3HA: Not all populations have the same meanF = MSB/MSW = 1,474,542,579/87,813,791 = 16.79Because the F test statistic = 16.79 > = 2.3778, we do reject the null hypothesis based on these sample data.B) H0: 1 = 2 = 3HA : Not all populations have the same meanF = MSB/MSW = 87,813,791 /1,474,542,579= 0.060Because the F test statistic = 0.060 < = 2.3778, we do not reject the null hypothesis based on these sample data.C) H0 : 1 = 2 = 3HA : Not all populations have the same meanF = SSW/MSW = 6,322,592,933/87,813,791 = 72Because the F test statistic = 72 > = 2.3778, we do reject the null hypothesis based on these sample data.D) H0 : 1 = 2 = 3HA : Not all populations have the same meanF = SSW/MSW = 6,322,592,933/1,474,542,579= 4.28Because the F test statistic = 4.28 > = 2.3778, we do reject the null hypothesis based on these sample data

Q: A two-factor analysis of variance is conducted to test the effect that price and advertising have on sales of a particular brand of bottled water. Each week a combination of particular levels of price and advertising are used and the sales amount is recorded. The computer results are shown below. ANOVA Source of Variation SS df MS F p-value F-crit Sample (advertising) 99.73324 1 99.73324 5.251652 0.034201 4.413873 Columns (price) 1150.432 2 575.2161 30.28914 1.74E-06 3.554557 Interaction 1577.526 2 788.7629 41.53387 1.8E-07 3.554557 Within 341.835 18 18.99083 Total 3169.526 23 Based on the results above and a 0.05 level of significance, which of the following is correct? A) There is no interaction between price and advertising, so results for individual factors may be misleading. B) There is interaction between price and advertising, so the above results for individual factors may be misleading. C) There is no interaction between price and advertising, and both factors significantly affect sales. D) There is interaction between price and advertising, so the above results conclusively show that both factors affect price.

Q: A two-factor analysis of variance is conducted to test the effect the price and advertising have on sales of a particular brand of bottled water. Each week a combination of particular levels of price and advertising are used and the sales level is recorded. The computer results are shown below. ANOVA Source of Variation SS df MS F p-value F-crit Sample (advertising) 99.73324 1 99.73324 5.251652 0.034201 4.413873 Columns (price) 1150.432 2 575.2161 30.28914 1.74E-06 3.554557 Interaction 1577.526 2 788.7629 41.53387 1.8E-07 3.554557 Within 341.835 18 18.99083 Total 3169.526 23 Based on the results above, which of the following is correct? A) 1 level of advertising and 2 levels of price were used. B) 3 levels of adverting and 2 levels of price were used. C) 2 levels of advertising and 3 levels of price were used. D) There were a total of 6 different treatments.

Q: A two-factor analysis of variance is conducted to test the effect the price and advertising have on sales of a particular brand of bottled water. Each week a combination of particular levels of price and advertising are used and the sales level is recorded. The computer results are shown below. ANOVA Source of Variation SS df MS F p-value F-crit Sample (advertising) 99.73324 1 99.73324 5.251652 0.034201 4.413873 Columns (price) 1150.432 2 575.2161 30.28914 1.74E-06 3.554557 Interaction 1577.526 2 788.7629 41.53387 1.8E-07 3.554557 Within 341.835 18 18.99083 Total 3169.526 23 How many replications were used in this study? A) 2 B) 3 C) 4 D) 5

Q: A national car rental company recently conducted a study recently in which cars with automatic and standard transmissions (factor A-Sample) were rented to male and female customers (factor B-Columns). Three customers in each category were randomly selected and the miles driven per day was recorded as follows: Based on these sample data, and alpha = .05, which of the following statements is true? A) The means for factor A are significantly different. B) There is no significant interaction between factors A and B. C) The means for factor B are significantly different. D) All of the above statements are true.

Q: A national car rental company recently conducted a study recently in which cars with automatic and standard transmissions (factor A-Sample) were rented to male and female customers (factor B-Columns). Three customers in each category were randomly selected and the miles driven per day was recorded as follows: Based on the design of this study, how many degrees of freedom will be associated with the mean square for factor A? A) 1 B) 2 C) 3 D) 8

Q: Considering the following printout for a two-factor ANOVA study, which of the following is the number of replications used? A) 2 B) 5 C) 4 D) Can't be determined without more information.

Q: Considering the following printout for a two-factor ANOVA design, which of the following is a proper conclusion to reach? A) There is no significant interaction between the two factors. B) The levels of factor A (Sample) have significantly different means. C) The levels of factor B (Columns) have significantly different means. D) The total number of observations is 47.

Q: Considering the following printout from a two-factor ANOVA design, how many levels of factor A (Sample) were there in this study? A) 4 B) 3 C) 2 D) 6

Q: Which of the following is the minimum number of required replications per cell for a two-factor ANOVA design if you plan to test for interactive effects between factors A and B? A) 3 B) 1 C) 2 D) 5

Q: Which type of ANOVA can include interaction? A) One-way B) Randomized complete block C) Two-factor D) All types of ANOVA

Q: Which of the following is NOT one of the assumptions required by the randomized block design? A) The populations are normally distributed. B) The populations have equal means. C) The observations within samples are independent. D) The data measurement must be interval or ratio level.

Q: A car company is interested in testing to see whether the mean miles that a car engine will last without changing oil is the same or different depending on which brand of oil is used. The engineers also wish to control for the type of transmission (manual or automatic) that is used. To conduct this test, the car company obtains enough engines so that all four oil brands can be tested in a design that involves no replication. The following data reflect the miles the engine lasted until problems were encountered. Data are in thousands of miles. Oil 1 Oil 2 Oil 3 Oil 4 Manual 58 40.8 60.8 40 Automatic 83 65.9 90.5 68.6 Assuming that the hypothesis tests are conducted using a significance level equal to 0.05, which of the following statements is true? A) Based on the data, Oil 1 and Oil 3 give statistically more miles on average than do the other two oils. B) The type of transmission does seem to have an impact on the mean miles that an engine will last. C) The F-critical value for testing whether blocking is effective is 10.128. D) All of the above are true.

Q: A test is conducted to compare three different income tax software packages to determine whether there is any difference in the average time it takes to prepare income tax returns using the three different software packages. Ten different persons' income tax returns are done by each of the three software packages and the time is recorded for each. The computer results are shown below. SUMMARY Count Sum Average Variance 1 3 9 3 1 2 3 30 10 1 3 3 12 4 0 4 3 6.5 2.166667 0.583333 5 3 25 8.333333 2.333333 6 3 7 2.333333 1.083333 7 3 10 3.333333 0.333333 8 3 18 6 1 9 3 33.5 11.16667 0.583333 10 3 4.5 1.5 0.25 Software A 10 47.5 4.75 12.95833 Software B 10 47.5 4.75 10.79167 Software C 10 60.5 6.05 13.46944 ANOVA Source of Variation SS df MS F P-value F crit Rows 329.9083 9 36.65648 130.227 1.6E-14 2.456281 Columns 11.26667 2 5.633333 20.01316 2.66E-05 3.554557 Error 5.066667 18 0.281481 Total 346.2417 29 Assuming that the hypothesis tests are conducted using a significance level equal to 0.05, the Fisher's LSD value for multiple comparisons is: A) approximately 0.4985. B) about 0.91. C) approximately 1.91. D) about 0.5387.

Q: A test is conducted to compare three different income tax software packages to determine whether there is any difference in the average time it takes to prepare income tax returns using the three different software packages. Ten different persons' income tax returns are done by each of the three software packages and the time is recorded for each. The computer results are shown below. SUMMARY Count Sum Average Variance 1 3 9 3 1 2 3 30 10 1 3 3 12 4 0 4 3 6.5 2.166667 0.583333 5 3 25 8.333333 2.333333 6 3 7 2.333333 1.083333 7 3 10 3.333333 0.333333 8 3 18 6 1 9 3 33.5 11.16667 0.583333 10 3 4.5 1.5 0.25 Software A 10 47.5 4.75 12.95833 Software B 10 47.5 4.75 10.79167 Software C 10 60.5 6.05 13.46944 ANOVA Source of Variation SS df MS F P-value F crit Rows 329.9083 9 36.65648 130.227 1.6E-14 2.456281 Columns 11.26667 2 5.633333 20.01316 2.66E-05 3.554557 Error 5.066667 18 0.281481 Total 346.2417 29 Based on these results and using a 0.05 level of significance which is correct regarding the primary hypothesis? A) The three software packages are not all the same because p-value = 1.6E-14 is less than 0.05. B) The three software packages are all the same because p-value = 1.6 is greater than 0.05. C) The three software packages are not all the same because p-value = 2.66E-5 is less than 0.05. D) The three software packages are all the same because p-value = 2.66 is greater than 0.05.

Q: A test is conducted to compare three different income tax software packages to determine whether there is any difference in the average time it takes to prepare income tax returns using the three different software packages. Ten different persons' income tax returns are done by each of the three software packages and the time is recorded for each. The computer results are shown below. SUMMARY Count Sum Average Variance 1 3 9 3 1 2 3 30 10 1 3 3 12 4 0 4 3 6.5 2.166667 0.583333 5 3 25 8.333333 2.333333 6 3 7 2.333333 1.083333 7 3 10 3.333333 0.333333 8 3 18 6 1 9 3 33.5 11.16667 0.583333 10 3 4.5 1.5 0.25 Software A 10 47.5 4.75 12.95833 Software B 10 47.5 4.75 10.79167 Software C 10 60.5 6.05 13.46944 ANOVA Source of Variation SS df MS F P-value F crit Rows 329.9083 9 36.65648 130.227 1.6E-14 2.456281 Columns 11.26667 2 5.633333 20.01316 2.66E-05 3.554557 Error 5.066667 18 0.281481 Total 346.2417 29 Based on these results and using a 0.05 level of significance which is correct regarding blocking? A) Blocking was not effective because p-value = 2.66 is greater than 0.05. B) Blocking was effective because p-value = 2.66E - 5 is less than 0.05. C) Blocking was not effective because p-value = 1.6 is greater than 0.05. D) Blocking was effective because p-value = 1.6E-14 is less than 0.05.

Q: A large orchard owner in the state of Washington is interested in determining whether the mean number of bushels of peaches per acre is the same or different depending on the type of tree that is used. He also thinks that production may be affected by the type of fertilizer that is used. To test, he has set up a test in which a one-acre plot of peach trees with a combination each of 5 varieties and 3 fertilizer types are studied. The following data reflect the number of bushels of peaches on each acre plot. Tree Type 1 Tree Type 2 Tree Type 3 Tree Type 4 Tree Type 5 Fertilizer A 300 400 200 500 400 Fertilizer B 150 200 100 150 200 Fertilizer C 300 300 400 200 500 Assuming that the hypothesis tests will be conducted using an alpha equal 0.05 level, what is the value of the Fisher's LSD critical value for doing the multiple comparisons? A) Approximately 16.78 B) About 11.30 C) Approximately 186.7 D) Need to know the number of trees planted on each acre.

Q: A large orchard owner in the state of Washington is interested in determining whether the mean number of bushels of peaches per acre is the same or different depending on the type of tree that is used. He also thinks that production may be affected by the type of fertilizer that is used. To test, he has set up a test in which a one-acre plot of peach trees with a combination each of 5 varieties and 3 fertilizer types are studied. The following data reflect the number of bushels of peaches on each acre plot. Tree Type 1 Tree Type 2 Tree Type 3 Tree Type 4 Tree Type 5 Fertilizer A 300 400 200 500 400 Fertilizer B 150 200 100 150 200 Fertilizer C 300 300 400 200 50 Assuming that the hypothesis tests will be conducted using an alpha equal 0.05 level, which of the following is true? A) The total sum of squares is approximately 4,570,900. B) The grower was justified in controlling for the fertilizer type since the test shows that blocking was effective. C) Based on the data, the grower can conclude that there is a difference in mean production of peaches across the different types of tree. D) A, B and C are all true.

Q: A golf ball manufacturer has three dimple patterns it is interested in analyzing to see whether one results in longer driving distances. However, it also wishes to control for the material the ball is made from since it believes that the material might affect driving distance. Four materials can be used. The following data represent the results of tests in which each combination of dimple pattern and cover material were used and the length of the ball hit by a robot has been recorded. The test will be conducted using an alpha = 0.05 level. Pattern 1 Pattern 2 Pattern 3 Material A 257 248 260 Material B 250 247 255 Material C 230 260 240 Material D 266 256 280 Given these data, what is the value of Fisher's Least Significant Difference critical value? A) Approximately 19.06 B) 2.4469 C) About 7.65 D) None of the above

Q: A golf ball manufacturer has three dimple patterns it is interested in analyzing to see whether one results in longer driving distances. However, it also wishes to control for the cover material the ball is made from since it believes that the material might affect driving distance. Four materials can be used. The following data represent the results of tests in which each combination of dimple pattern and cover material were used and the length of the ball hit by a robot has been recorded. The test will be conducted using an alpha = 0.05 level. Pattern 1 Pattern 2 Pattern 3 Material A 257 248 260 Material B 250 247 255 Material C 230 260 240 Material D 266 256 280 Given these data, which of the following statements is true? A) There is no basis for concluding that mean driving distance is different for the different dimple patterns. B) There is no basis for concluding that mean driving distance is different for the different cover materials. C) Both A and B are true. D) Neither A nor B is true.

Q: A major consumer group recently undertook a study to determine whether automobile customers would rate the quality of cars differently whether they were manufactured in the U.S., Europe, or Japan. To conduct this test, a sample of 20 individuals was asked to look at mid-range model cars made in each of the three countries. The individuals in the sample were then asked to provide a rating for each car on a scale of 1 to 1000. The following computer output resulted, and the tests were conducted using a significance level equal to 0.05. ANOVA: Two-Factor Without Replication Based upon the data, which of the following statements is true? A) Blocking was effective. B) Blocking was not effective. C) The primary null hypothesis should not be rejected. D) The averages for the 20 people are not all the same.

Q: Recently, a department store chain was interested in determining if there was a difference in the mean number of customers who enter the three stores in Seattle. The analysts set up a study in which the number of people entering the stores was counted depending on whether the day of the week was Saturday, Sunday, or a weekday. The following data were collected: Store A Store B Store C Saturday 176 300 56 Sunday 145 290 40 Weekday 108 150 40 Given this format and testing using an alpha level equal to 0.05, which of the following statements is true? A) The total degrees of freedom is 9. B) The between blocks degrees of freedom equals 8. C) The between samples degrees of freedom equals 3. D) The within sample degrees of freedom equals 4.

Q: Recently, a department store chain was interested in determining if there was a difference in the mean number of customers who enter the three stores in Seattle. The analysts set up a study in which the number of people entering the stores was counted depending on whether the day of the week was Saturday, Sunday, or a weekday. The following data were collected: Store A Store B Store C Saturday 176 300 56 Sunday 145 290 40 Weekday 108 150 40 Given this format, which of the following is true? A) The day of the week would be considered the blocking factor in the study. B) There are six treatments. C) This is a balanced design since the number of rows and columns is equal. D) All of the above are true.

Q: In a randomized complete block design analysis of variance, which of the following correctly describes the number of degrees of freedom associated with the between sum of squares? A) One less than the number of populations involved B) One less than the number of blocks C) One less than the combined sample size in the experiment D) One less than the total number of observations

Q: In a randomized complete block design analysis of variance, how many factors are there to be analyzed? A) Depends on the sample size in each treatment B) One factor, but multiple levels C) Two factors D) Can't be determined without additional information

Q: Which of the following describes a treatment in a randomized complete block analysis of variance? A) A treatment is a combination of one level of each factor. B) A treatment is a level associated with each factor of the experiment. C) A treatment is another term for the data that are collected in the experiment. D) A treatment is considered to be the analysis that is performed on the sample data.

Q: To test the mileage efficiency of three new car models, random samples of various sample sizes were selected from each of the three cars and the mpg data obtained are shown below. Model A Model B Model C 37 43 28 33 39 32 36 35 33 38 38 40 Based on the sample date, one can conclude that A) all three car models have the same mean mpg. B) at least two car models have different mpgs. C) Model C has a higher mpg than Model A. D) None of the above

Q: In a one-way ANOVA, which of the following is true? A) The degrees of freedom associated with the between sum of squares is equal to one less than the number of populations. B) The critical value will be an F-value from the F distribution. C) If the null hypothesis is rejected, it may still be possible that two or more of the population means are equal. D) All of the above

Q: In a one-way design, which of the following is true? A) The populations must have equal means. B) The sample sizes must be equal. C) The mean squares between will be larger than the mean squares within if the null hypothesis is rejected. D) The sample sizes must all differ.

Q: In order for a one-way analysis of variance to be considered a balanced design, which of the following must hold? A) The population variances must be equal. B) The sample sizes selected from each population must be equal. C) The study must have the same number of rows as it does columns. D) All of the above are true.

Q: A fast food chain operation is interested in determining whether the mean per customer purchase differs by day of the week. To test this, it has selected random samples of customers for each day of the week. The analysts then ran a one-way analysis of variance generating the following output: ANOVA: Single Factor Based upon this output, which of the following statements is true if the test is conducted at the 0.05 level of significance? A) There is no basis for concluding that mean sales is different for the different days of the week. B) Based on the p-value, the null hypothesis should be rejected since the p-value exceeds the alpha level. C) The experiment is conducted as an unbalanced design. D) Based on the critical value, the null should be rejected.

Q: An Internet service provider is interested in testing to see if there is a difference in the mean weekly connect time for users who come into the service through a dial-up line, DSL, or cable Internet. To test this, the ISP has selected random samples from each category of user and recorded the connect time during a week period. The following data were collected: Dial Up DSL Cable 19.2 40.6 39.5 17.7 40 42.3 17.2 41.5 47 18.9 30.5 45.4 26.9 46.8 41.1 22.6 43.2 31.2 39.9 41.9 49.3 Based upon these data and a significance level of 0.05, which of the following statements is true? A) The F-critical value for the test is 3.555 B) The test statistic is approximately 43.9 C) The null hypothesis should be rejected and conclude that the mean connect times for the three user categories are not all equal. D) All of the above are true.

Q: Assume you are conducting a one-way analysis of variance using a 0.05 level of significance and have found that the p-value = 0.02. Which of the follow is correct regarding what you can conclude? A) Do not reject the null hypothesis; the means are all the same. B) Reject the null hypothesis; the means are not all the same. C) Do not reject the null hypothesis; the means are not all the same. D) Reject the null hypothesis; the means are all the same.

Q: An Internet service provider is interested in testing to see if there is a difference in the mean weekly connect time for users who come into the service through a dial-up line, DSL, or cable Internet. To test this, the ISP has selected random samples from each category of user and recorded the connect time during a week period. The following data were collected: Dial Up DSL Cable 19.2 40.6 39.5 17.7 40 42.3 17.2 41.5 47 18.9 30.5 45.4 26.9 46.8 41.1 22.6 43.2 31.2 39.9 41.9 49.3 Assuming that the test is to be conducted at a 0.01 level of significance, what would the critical value be for this test? A) F = 1.93 B) F = 3.555 C) t = 2.8784 D) F = 6.013

Q: In a one-way analysis of variance test in which the levels of the factor being analyzed are randomly selected from a large set of possible factors, the design is referred to as: A) a fixed-effects design. B) a random-effects design. C) an undetermined results design. D) a balanced design.

Q: The State Transportation Department is thinking of changing its speed limit signs. It is considering two new options in addition to the existing sign design. At question is whether the three sign designs will produce the same mean speed. To test this, the department has conducted a limited test in which a stretch of roadway was selected. With the original signs up, a random sample of 30 cars was selected and the speeds were measured. Then, on different days, the two new designs were installed, 30 cars each day were sampled, and their speeds were recorded. Suppose that the following summary statistics were computed based on the data: Based on these sample results and a significance level equal to 0.05, assuming that the null hypothesis of equal means has been rejected, the Tukey-Kramer critical range is: A) 1.96. B) approximately 4.0. C) Can't be determined without more information D) None of the above

Q: In conducting a one-way analysis of variance where the test statistic is less than the critical value, which of the following is correct? A) Conclude that the means are not all the same and that that the Tukey-Kramer procedure should be conducted. B) Conclude that the means are not all the same and that that the Tukey-Kramer procedure is not needed. C) Conclude that all means are the same and that the Tukey-Kramer procedure should be conducted. D) Conclude that all means are the same and there is no need to conduct the Tukey-Kramer procedure.

Q: The State Transportation Department is thinking of changing its speed limit signs. It is considering two new options in addition to the existing sign design. At question is whether the three sign designs will produce the same mean speed. To test this, the department has conducted a limited test in which a stretch of roadway was selected. With the original signs up, a random sample of 30 cars was selected and the speeds were measured. Then, on different days, the two new designs were installed, 30 cars each day were sampled, and their speeds were recorded. Suppose that the following summary statistics were computed based on the data: Based on these sample results and significance level equal to 0.05, the sum of squares between is: A) approximately 3,586. B) approximately 2,430. C) approximately 1,215. D) None of the above

Q: The State Transportation Department is thinking of changing its speed limit signs. It is considering two new options in addition to the existing sign design. At question is whether the three sign designs will produce the same mean speed. To test this, the department has conducted a limited test in which a stretch of roadway was selected. With the original signs up, a random sample of 30 cars was selected and the speeds were measured. Then, on different days, the two new designs were installed, 30 cars each day were sampled, and their speeds were recorded. Suppose that the following summary statistics were computed based on the data: The appropriate test to conduct to determine if the population means are equal is: A) Hartley's F-max test. B) one-way analysis of variance. C) three sample t-test. D) randomized complete block analysis of variance.

Q: The State Transportation Department is thinking of changing its speed limit signs. It is considering two new options in addition to the existing sign design. At question is whether the three sign designs will produce the same mean speed. To test this, the department has conducted a limited test in which a stretch of roadway was selected. With the original signs up, a random sample of 30 cars was selected and the speeds were measured. Then, on different days, the two new designs were installed, 30 cars each day were sampled, and their speeds were recorded. Suppose that the following summary statistics were computed based on the data: Based on these sample results and significance level equal to 0.05, what is the critical value for this hypothesis test? A) F = approximately 3.15 B) F = approximately 4.90 C) F = approximately 29.47 D) F = approximately 2.70

Q: A hotel chain has four hotels in Oregon. The general manager is interested in determining whether the mean length of stay is the same or different for the four hotels. She selects a random sample of n = 20 guests at each hotel and determines the number of nights they stayed. Assuming that she plans to test this using an alpha level equal to 0.05, which of the following is the appropriate alternative hypothesis?A) H0 : 1 = 2 = 3 = 4B) H0 : 1 2 3 4C) Not all population means are equal.D) 1 = 2 = 3 = 4

Q: A hotel chain has four hotels in Oregon. The general manager is interested in determining whether the mean length of stay is the same or different for the four hotels. She selects a random sample of n = 20 guests at each hotel and determines the number of nights they stayed. Assuming that she plans to test this using an alpha level equal to 0.05, which of the following is the correct critical value? A) F = 3.04 B) F = 2.76 C) t = 1.9917 D) F = 2.56

Q: Which of the following is an assumption for the one-way analysis of variance experimental design? A) All populations are normally distributed. B) The populations have equal variances. C) The observations are independent. D) All of the above

Q: In a two-factor ANOVA design with replication, if the null hypothesis pertaining to interaction between factors A and B is rejected, then it is recommended that the hypothesis tests for factor A and factor B individually should not be conducted because the conclusions might be misleading.

Q: In a two-factor ANOVA design with replication, the null hypothesis for testing whether interaction exists is that no interaction exists. The alternative hypothesis is that interaction does exist.

Q: In a two-factor ANOVA with replication in which all hypotheses are to be tested using an alpha = .05 level, if the p-value for interaction is .03467, the decision maker should conclude that no interaction is present.

Q: Six food critics each visited and rated four different restaurants. Each critic visited each restaurant on three separate occasions and recorded a score for each visit. Assume that results show that there is an interaction. This would mean that, for example, which restaurant is rated the highest depends on which critic does the rating.

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