Q&A Hero

Q: The manager of the quality department for a tire manufacturing company wants to know the average tensile strength of rubber used in making a certain brand of radial tire. The population is normally distributed, and the population standard deviation is known. She uses a z test to test the null hypothesis that the mean tensile strength is less than or equal to 800 pounds per square inch. The calculated z test statistic is a positive value that leads to a p-value of .067 for the test. If the significance level is .10, the null hypothesis would be rejected.

Q: A sociologist develops a test designed to measure attitudes about disabled people and gives the test to 16 randomly selected subjects. Their mean score is 71.2 with a standard deviation of 10.5. Construct the 99 percent confidence interval for the mean score of all subjects. A. [40.26, 102.14] B. [63.46, 78.94] C. [60.66, 81.74] D. [64.44, 77.96] E. [63.21, 79.19]

Q: An environmental group at a local college is conducting independent tests to determine the distance a particular make of automobile will travel while consuming only 1 gallon of gas. They test a sample of five cars and obtain a mean of 28.2 miles. How many cars should the environmental group test if they wish to estimate μ, mean miles per 1 gallon, to within 0.5 miles and be 99 percent confident? Assume a population standard deviation of 2.7 miles. A. 25 B. 124 C. 194 D. 618 E. 619

Q: An environmental group at a local college is conducting independent tests to determine the distance a particular make of automobile will travel while consuming only 1 gallon of gas. They test a sample of five cars and obtain a mean of 28.2 miles. Assuming that the standard deviation is 2.7 miles, find the 95 percent confidence interval for the mean distance traveled by all such cars using 1 gallon of gas. A. [26.16, 30.24] B. [20.70, 35.70] C. [24.85, 31.55] D. [26.70, 29.70] E. [25.83, 30.57]

Q: A local company makes a candy that is supposed to weigh 1.00 ounces. A random sample of 25 pieces of candy produces a mean of 0.996 ounces with a standard deviation of 0.004 ounces. How many pieces of candy must we sample if we want to be 99 percent confident that the sample mean is within 0.001 ounces of the true mean? A. 126 B. 124 C. 107 D. 12 E. 6

Q: A local company makes a candy that is supposed to weigh 1.00 ounces. A random sample of 25 pieces of candy produces a mean of 0.996 ounces with a standard deviation of 0.004 ounces. Construct a 98 percent confidence interval for the mean weight of all such candy. A. [0.9645, 1.0275] B. [0.9956, 0.9964] C. [0.9860, 1.0060] D. [0.9940, 0.9980] E. [0.9942, 0.9978]

Q: The coffee and soup machine at the local subway station is supposed to fill cups with 6 ounces of soup. Ten cups of soup are bought with results of a mean of 5.93 ounces and a standard deviation of 0.13 ounces. How large a sample of soups would we need to be 95 percent confident that the sample mean is within 0.03 ounces of the population mean? A. 97 B. 96 C. 73 D. 62 E. 10

Q: The coffee and soup machine at the local subway station is supposed to fill cups with 6 ounces of soup. Ten cups of soup are bought with results of a mean of 5.93 ounces and a standard deviation of 0.13 ounces. Construct a 99 percent confidence interval for the true machine-fill amount. A. [5.75, 5.99] B. [5.85, 6.05] C. [5.90, 6.00] D. [5.70, 6.16] E. [5.80, 6.06]

Q: Health insurers and the federal government are both putting pressure on hospitals to shorten the average length of stay (LOS) of their patients. In 2003, the average LOS for non-heart patients was 4.6 days. A random sample of 20 hospitals in one state had a mean LOS for non-heart patients in 2008 of 3.8 days and a standard deviation of 1.2 days. How large a sample of hospitals would we need to be 99 percent confident that the sample mean is within 0.5 days of the population mean?A. 3B. 7C. 32D. 48E. 96

Q: Health insurers and the federal government are both putting pressure on hospitals to shorten the average length of stay (LOS) of their patients. In 2003, the average LOS for non-heart patients was 4.6 days. A random sample of 20 hospitals in one state had a mean LOS for non-heart patients in 2008 of 3.8 days and a standard deviation of 1.2 days. Calculate a 95 percent confidence interval for the population mean LOS for non-heart patients in these hospitals in 2008. A. [3.24, 4.36] B. [3.67, 3.93] C. [3.34, 4.26] D. [3.38, 4.22] E. [3.27, 4.33]

Q: At the end of 1990, 1991, and 1992, the average prices of a share of stock in a portfolio were $34.83, $34.65, and $31.26 respectively. To investigate the average share price at the end of 1993, a random sample of 30 stocks was drawn and their closing prices on the last trading day of 1993 were observed with a mean of 33.583 and a standard deviation of 19.149. Estimate the average price of a share of stock in the portfolio at the end of 1993 with a 90 percent confidence interval. A. [27.646, 39.523] B. [26.732, 40.434] C. [32.514, 34.651] D. [32.533, 34.633] E. [32.269, 34.897]

Q: In a random sample of 651 computer scientists who subscribed to a web-based daily news update, it was found that the average salary was $46,816 with a population standard deviation of $12,557. Calculate a 91 percent confidence interval for the mean salary of computer scientists. A. [$25,469, $68,163] B. [$46,592, $47,040] C. [$46,157, $47,475] D. [$46,783, $46,849] E. [$45,981, $47,650]

Q: Unoccupied seats on flights cause airlines to lose revenue. Suppose a large airline wants to estimate its average number of unoccupied seats per flight over the past year. 225 flight records are randomly selected and the number of unoccupied seats is noted, with a sample mean of 11.6 seats and a standard deviation of 4.1 seats. How many flights should we select if we wish to estimate μ to within 2 seats and be 95 percent confident? A. 130 B. 65 C. 33 D. 17 E. 12

Q: Unoccupied seats on flights cause airlines to lose revenue. Suppose a large airline wants to estimate its average number of unoccupied seats per flight over the past year. 225 flight records are randomly selected and the number of unoccupied seats is noted, with a sample mean of 11.6 seats and a standard deviation of 4.1 seats. Calculate a 90 percent confidence interval for μ, the mean number of unoccupied seats per flight during the past year. A. [4.86, 18.34] B. [11.25, 11.95] C. [11.57, 11.63] D. [11.15, 12.05] E. [11.30, 12.20]

Q: Researchers have studied the role that the age of workers has in determining the hours per month spent on personal tasks. A sample of 1,686 adults were observed for one month. The data follow. Construct a 98 percent confidence interval for the mean hours spent on personal tasks for 25- to 44-year-olds. A. [3.96, 4.12] B. [3.97, 4.11] C. [3.98, 4.10] D. [2.16, 5.92] E. [3.95, 4.13]

Q: A psychologist is collecting data on the time it takes to learn a certain task. For 50 randomly selected adult subjects, the sample mean is 16.40 minutes and the sample standard deviation is 4.00 minutes. Construct the 95 percent confidence interval for the mean time required by all adults to learn the task. A. [8.56, 24.24] B. [15.47, 17.33] C. [16.24, 16.56] D. [15.26, 17.54] E. [17.12, 48.48]

Q: In a study of factors affecting whether soldiers decide to reenlist, 320 subjects were measured for an index of satisfaction. The sample mean is 28.8 and the sample standard deviation is 7.3. Use the given sample data to construct the 98 percent confidence interval for the population mean for level of satisfaction. A. [27.85, 29.75] B. [27.96, 29.64] C. [11.82, 45.78] D. [28.75, 28.85] E. [28.60, 29.00]

Q: The U.S. Department of Health and Human Services collected sample data for 772 males between the ages of 18 and 24. That sample group has a mean height of 69.7 inches with a standard deviation of 2.8 inches. Find the 99 percent confidence interval for the mean height of all males between the ages of 18 and 24. A. [63.19, 76.21] B. [62.49, 76.91] C. [69.65, 69.75] D. [69.47, 69.93] E. [69.44, 69.96]

Q: The state highway department is studying traffic patterns on one of the busiest highways in the state. As part of the study, the department needs to estimate the average number of vehicles that pass an intersection each day. A random sample of 64 days gives us a sample mean of 14,205 cars and a sample standard deviation of 1,010 cars. After calculating the confidence interval, the highway department officials decide that the precision is too low for their needs. They feel the precision should be 300 cars. Given this precision, and needing to be 99 percent confident, how many days do they need to sample? A. 109 B. 80 C. 79 D. 62 E. 9

Q: The state highway department is studying traffic patterns on one of the busiest highways in the state. As part of the study, the department needs to estimate the average number of vehicles that pass an intersection each day. A random sample of 64 days gives us a sample mean of 14,205 cars and a sample standard deviation of 1,010 cars. What is the 98 percent confidence interval estimate of , the mean number of cars passing the intersection?

Q: A company is interested in estimating , the mean number of days of sick leave taken by its employees. Their statistician randomly selects 100 personnel files and notes the number of sick days taken by each employee. The sample mean is 12.2 days, and the sample standard deviation is 10 days. How many personnel files would the statistician have to select in order to estimate to within 2 days with a 99 percent confidence interval?A. 2B. 13C. 136D. 165E. 173

Q: A company is interested in estimating , the mean number of days of sick leave taken by its employees. Their statistician randomly selects 100 personnel files and notes the number of sick days taken by each employee. The sample mean is 12.2 days, and the sample standard deviation is 10 days. Calculate a 95 percent confidence interval for

Q: In a manufacturing process, we are interested in measuring the average length of a certain type of bolt. Based on a preliminary sample of 9 manufactured bolts, the sample standard deviation is .3 inches. How many bolts should be sampled in order to make us 95 percent confident that the sample mean bolt length is within .02 inches of the true mean bolt length?

Q: In a manufacturing process, we are interested in measuring the average length of a certain type of bolt. Past data indicate that the standard deviation is .25 inches. How many manufactured bolts should be sampled in order to make us 95 percent confident that the sample mean bolt length is within .02 inches of the true mean bolt length?A. 25B. 49C. 423D. 601E. 1225

Q: The internal auditing staff of a local lawn-service company performs a sample audit each quarter to estimate the proportion of accounts that are current (between 0 and 60 days after billing). The historical records show that over the past 8 years 70 percent of the accounts have been current. Determine the sample size needed in order to be 99 percent confident that the sample proportion of the current customer accounts is within .03 of the true proportion of all current accounts for this company. A. 1842 B. 1549 C. 897 D. 632 E. 1267

Q: The internal auditing staff of a local lawn-service company performs a sample audit each quarter to estimate the proportion of accounts that are delinquent (more than 90 days overdue). For this quarter, the auditing staff randomly selected 400 customer accounts and found that 80 of these accounts were delinquent. What is the 95 percent confidence interval for the proportion of all delinquent customer accounts at this company? A. .1608 to .2392 B. .1992 to .2008 C. .1671 to .2329 D. .1485 to .2515 E. .1714 to .2286

Q: In a manufacturing process, a random sample of 36 manufactured bolts has a mean length of 3 inches with a standard deviation of .3 inches. What is the 99 percent confidence interval for the true mean length of the manufactured bolt? A. 2.902 to 3.098 B. 2.884 to 3.117 C. 2.864 to 3.136 D. 2.228 to 3.772 E. 2.802 to 3.198

Q: In a manufacturing process a random sample of 9 manufactured bolts has a mean length of 3 inches with a standard deviation of .3 inches. What is the 95 percent confidence interval for the true mean length of the manufactured bolt?A. 2.804 to 3.196B. 2.308 to 3.692C. 2.769 to 3.231D. 2.412 to 3.588E. 2.814 to 3.186

Q: In a manufacturing process, a random sample of 9 manufactured bolts has a mean length of 3 inches with a variance of .09. What is the 90 percent confidence interval for the true mean length of the manufactured bolt?A. 2.8355 to 3.1645B. 2.5065 to 3.4935C. 2.4420 to 3.5580D. 2.8140 to 3.1860E. 2.9442 to 3.0558

Q: A researcher for a paint company is measuring the level of a certain chemical contained in a particular type of paint. If the paint contains too much of this chemical, the quality of the paint will be compromised. On average, each can of paint contains 10 percent of the chemical. How many cans of paint should the sample contain if the researcher wants to be 98 percent certain of being within 1 percent of the true proportion of this chemical? A. 4870 B. 1107 C. 26 D. 645

Q: The tolerance interval of 95.44 percent is ________ a 95.44 percent confidence interval. A. the same width as B. narrower than C. wider than

Q: In determining the sample size to estimate a population proportion, as p approaches .5, the calculated value of the sample size ______________. A. stays the same B. decreases C. increases

Q: A confidence interval for the population mean is an interval constructed around the ____________. A. sample mean B. population mean C. z test statistic D. t test statistic

Q: If everything else is held constant, decreasing the margin of error causes the required sample size to ____________. A. stay the same B. decrease C. increase

Q: As the margin of error decreases, the width of the confidence interval _______________. A. stays the same B. decreases C. increases

Q: As the stated confidence level decreases, the width of the confidence interval _______________. A. stays the same B. decreases C. increases

Q: As the standard deviation () decreases, the width of the confidence interval _______________.A. stays the sameB. decreasesC. increases

Q: As the significance level increases, the width of the confidence interval _______________.A. stays the sameB. decreasesC. increases

Q: When establishing the confidence interval for the average weight of a cereal box, assume that the population standard deviation is known to be 2 ounces. Based on a sample, the average weight of a sample of 20 boxes is 16 ounces. The appropriate test statistic to use is ________.A. tB. zC. xD. p

Q: As the sample size n increases, the width of the confidence interval _______________. A. stays the same B. decreases C. increases

Q: When constructing a confidence interval, as the confidence level required in estimating the mean increases, the width of the confidence interval ______________. A. stays the same B. decreases C. increases

Q: Assuming the same level of significance , as the sample size increases, the value of t/2 ___________ approaches the value of z/2.A. alwaysB. sometimesC. never

Q: There is little difference between the values of t/2 and z/2 whenA. the sample size is small.B. the sample size is large.C. the sample mean is small.D. the sample mean is large.E. the sample standard deviation is small.

Q: When a confidence interval for a population proportion is constructed for a sample size n = 30 and the value of = .4, the interval is based on A. the z distribution. B. the t distribution. C. the exponential distribution. D. the Poisson distribution. E. None of the other choices is correct.

Q: When solving for the sample size needed to compute a 95 percent confidence interval for a population proportion p, having a given error bound E, we choose a value of thatA. makes as small as reasonably possible.B. makes as large as reasonably possible.C. makes as close to .5 as reasonably possible.D. makes as close to .25 as reasonably possible.E. makes as large as reasonably possible and makes as close to .25 as reasonably possible.

Q: When the population is normally distributed, population standard deviation is unknown, and the sample size is n = 15, the confidence interval for the population mean is based onA. the z (normal) distribution.B. the t distribution.C. the binomial distribution.D. the Poisson distribution.E. None of the other choices is correct.

Q: When the level of confidence and sample size remain the same, a confidence interval for a population proportion, p, will be ______________ when is larger than when is smaller. A. wider B. narrower C. neither wider nor narrower (they will be the same)

Q: When the level of confidence and sample proportion remain the same, a confidence interval for a population proportion p based on a sample of n = 100 will be ______________ a confidence interval for p based on a sample of n = 400. A. wider than B. narrower than C. equal to

Q: When the sample size and the sample proportion remain the same, a 90 percent confidence interval for a population proportion p will be ______________ the 99 percent confidence interval for p. A. wider than B. narrower than C. equal to

Q: When the level of confidence and the sample size remain the same, a confidence interval for a population mean μ will be ________________ when the sample standard deviation s is small than when s is large. A. wider B. narrower C. neither wider nor narrower (they will be the same)

Q: When the level of confidence and sample standard deviation remain the same, a confidence interval for a population mean based on a sample of n = 100 will be ______________ a confidence interval for a population mean based on a sample of n = 50. A. wider than B. narrower than C. equal to

Q: When the sample size and sample standard deviation remain the same, a 99 percent confidence interval for a population mean, , will be _________________ the 95 percent confidence interval for .A. wider thanB. narrower thanC. equal to

Q: Which of the following is an advantage of a confidence interval estimate over a point estimate for a population parameter? A. Interval estimates are more precise than point estimates. B. Interval estimates are less accurate than point estimates. C. Interval estimates are both more accurate and more precise than point estimates. D. Interval estimates take into account the fact that the statistic being used to estimate the population parameter is a random variable.

Q: The width of a confidence interval will be A. narrower for 98 percent confidence than for 90 percent confidence. B. wider for a sample size of 64 than for a sample size of 36. C. wider for 99 percent confidence than for 95 percent confidence D. narrower for a sample size of 25 than for a sample size of 36. E. None of the other choices is correct.

Q: A confidence interval increases in width as A. the level of confidence increases. B. n decreases. C. s increases. D. All of the other choices are correct.

Q: When constructing a confidence interval for a population mean, if a population is normally distributed and a small sample is taken, then the distribution of is based on the ____________ distribution. A. z B. t C. neither the z nor the t distribution D. both the z and the t distribution

Q: When determining the sample size, if the value found is not an integer initially, you should ____________ choose the next highest integer value. A. always B. sometimes C. never

Q: As standard deviation increases, sample size _____________ to achieve a specified level of confidence. A. increases B. decreases C. remains the same

Q: The width of a confidence interval will be A. narrower for 99 percent confidence than for 95 percent confidence. B. wider for a sample size of 100 than for a sample size of 50. C. narrower for 90 percent confidence than for 95 percent confidence. D. wider when the sample standard deviation (s) is small than when s is large.

Q: The t distribution approaches the _______________ distribution as the sample size ___________. A. binomial, increases B. binomial, decreases C. z, decreases D. z, increases

Q: The exact spread of the t distribution depends on the _________. A. standard deviation of the sample B. sample size n C. number of degrees of freedom D. z distribution

Q: A tolerance interval is always longer than a corresponding confidence interval.

Q: A confidence interval for the population mean is meant to contain a specified percentage of the individual population measurements.

Q: A tolerance interval is meant to contain a specified percentage of the individual population measurements.

Q: When determining the sample size (n) for a confidence interval for , if past experience tells us that p is at least 0.8, use p = .2.

Q: When determining the sample size (n) for a confidence interval for , if you have no idea what value p is (it could be any value between 0 and 1), use p = .5.

Q: When determining the sample size (n) for a confidence interval for , if you are using a previous sample, use the reasonable value of that is closest to 0.25.

Q: The quantity [(N - n)/N] in the confidence intervals for and Ï„ is called the finite population correction and is always less than 1.

Q: If is unknown and there is no preliminary sample available to estimate , the range can be utilized to determine an estimate of when finding sample size.

Q: The more variable that the population measurements are, the larger the sample size that is needed to accurately estimate at a specific confidence level.

Q: When determining the sample size n, if the value found for n is 79.2, we would choose to sample 79 observations.

Q: When solving for the sample size needed to compute a 95 percent confidence interval for a population proportion p, having a given error bound E, we choose a value of that makes as small as reasonably possible.

Q: When the level of confidence and sample size remain the same, a confidence interval for a population proportion, p, will be narrower when is larger than when is smaller.

Q: When the level of confidence and sample proportion remain the same, a confidence interval for a population proportion, p, based on a sample of n = 100 will be wider than a confidence interval for p based on a sample of n = 400.

Q: When the level of confidence and the sample size remain the same, a confidence interval for a population mean μ will be wider when the sample standard deviation s is small than when s is large.

Q: When the level of confidence and sample standard deviation remain the same, a confidence interval for a population mean based on a sample of n = 100 will be narrower than a confidence interval for a population mean based on a sample of n = 50.

Q: When the sample size and sample standard deviation remain the same, a 99 percent confidence interval for a population mean, , will be narrower than the 95 percent confidence interval for .

Q: When the population is normally distributed and the population standard deviation is unknown, then for any sample size n, the sampling distribution of is based on the z distribution.

Q: First, a 90 percent confidence interval is constructed from a sample size of 100. Then, for the same identical data, a 92 percent confidence interval is constructed. The width of the 90 percent interval is wider than the 92 percent confidence interval.

Q: When constructing a confidence interval for a sample proportion, the t distribution is appropriate if the sample size is small.